Find p(-1) and p(5) for the function p(x)= 9x to the 4th power+9x to the third power- 11x to the 2nd power+12x+5

P(-1) = -18

P(5) = 6540

Step-by-step explanation:

Given the polynomial function

P(x) = 9x⁴+9x³-11x²+12x+5

We are to find p(-1) and p(5)

P(-1) = 9(-1)⁴+9(-1)³-11(-1)²+12(-1)+5

P(-1) = 9(1)+9(-1)-11(1)-12+5

P(-1) = 9-9-11-12+5

P(-1) = -23+5

P(-1) = -18

Get p(5)

P(5) = 9(5)⁴+9(5)³-11(5)²+12(5)+5

P(5) = 9(625)+9(125)-11(25)+65

P(5) = 5625+1125-275+65

P(5) = 6540

c

step-by-step explanation:

there is vertical asymptote at x = 2 and x = 0

vertical asymptote occurs at the points where the denominator is 0. so we can say that

x = 2 occurs when there is a factor (x-2) in the denominator, and

x = 0 occurs when there is a factor "x" in the denominator

thus, the denominator of the equation would have "x * (x-2)", this is option c only. that's the correct answer.