The inverse trig ratios should be thought of as undoing and operation much the same way we consider multiplication and division as inverses, or addition and subtraction. So long as we are dealing with acute angles in a right triangle, we can use inverse trig ratios to solve equations involving trig ratios. Solve the following example for x (in degrees), by taking the inverse sine of both sides. Round your answer to two decimal plaſes. sin(x)=1/7

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

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