Jeanette is trying to find the intersection point of these two lines: 2x + 3y = -2
5x – 3y = 16
She has decided to use substitution to find the point of intersection. Her plan is to solve the first equation for y,
and then to substitute the result into the second equation. Use Jeanette's idea to solve the system.

if the eqn of the parabola is f(x) = (x-4)(x+2), we need to mult. this out to find the coordinates of the vertex.

then f(x) = x^2 + 2x - 4x - 8, and f(x) = x^2 - 2x - 8.

one way in which you can find the vertex is to calculate x = -b / (2a).   here, that comes to

        )

x = = 1.   f(1) = 1^2 - 2(1) - 8 = - 9.   vertex is at (1, -9).

        2(1) 

find another point on the curve:   let x=0, for which y=-8.   then (0, -8) is on the curve.   plot the vertex and this point and draw a smooth parabola thru both.

hope this

can you take a photo of the screen?