The perimeter of a certain scalene triangle is 100 inches. The side lengths of the triangle are represented by 5x, 3x+30, and 2x+10, respectively. What

is the length, in inches, of the longest side of the triangle?

6

22

30

48

72

Longest side of triangle is 48 inches

Given information:

Perimeter of triangle = 100 inches

First side of triangle = 5x

Second side of triangle = 3x + 30

Third side of triangle = 2x + 10

Find:

Length in inches and longest side of the triangle

Computation:

Perimeter of triangle = Sum of all sides

So,

5x + (3x + 30) + (2x + 10) = 100

10x + 40 = 100

10x = 60

x = 10

So,

First side of triangle = 5x = 5(6)

First side of triangle = 30 inches

Second side of triangle = 3x + 30 = 3(6) + 30

Second side of triangle = 48 inches

Third side of triangle = 2x + 10 = 2(6) + 10

Third side of triangle = 22 inches

Longest side of triangle is 48 inches

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Step-by-step explanation:

Perimeter =100

the lengths of the sides are 5x+3x+30x+2x+10

5x+3x+30+2x+10=100

10x=100-40

10x=60

x=6

one side is 5x=30

one side 18+30=48

one side 2x+10=12+10=22

the longest side is 48

the answer is 18 units because there are 18 small cubes inside the rectangle

hope this and p.s i am also in k12

step-by-step explanation:

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