: The breakdown voltage of a randomly chosen diode of a certain type is known to be normally distributed with mean value 40 V and standard deviation 1.5 V. a) What is the probability that the voltage of a single diode is between 39 and 42

$75.00

step-by-step explanation:

i = prt

i = 1,5000 * 0.025 * 2

i = 75

5

step-by-step explanation:

(8+64)^2= 5184 < answer

step-by-step explanation:

2^3 = 8

4^3= 64

(8+64)^2 = 5184

this is a good question! i'll do some research and come back when i have the answer!