If you have a line that goes through (-1, 7) and (8, -2), what would the equation of the line be in point-slope form? Please use (8, -2) for x1 and y1.

y-9 = -1/12(x-8)

Step-by-step explanation:

To write an equation of a line perpendicular to the graph of y = 12x-3 and passing through the point, we will follow the following steps.

The standard form of point-slope form of the equation of a line is  given as

y − y1 = m(x − x1),

m is the slope of the unknown line

(x1, y1) is a point on the line.

Step 1: We need to calculate the slope of the known line first,

Given y = 12x-3

from the equation, m = 12 on comparison.

Step 2: get the slope of the unknown line. since the line given is perpendicular to the line y = 12x - 3, the product of their slope will be -1 i.e Mm = -1

M = -1/m

M is the slope of the unknown line

M = -1/12

Step 3: We will substitute M = -1/12 and the point (8, 9) into the point-slope form of the equation of a line i.e y − y1 = M(x − x1),

M = -1/12, x1 = 8 and y1 = 9

y-9 = -1/12(x-8)

all the angles opposite to the angle 150 would be 150 and all the angles that are next to 150 are 30 because they equal 180 it you add it up.

step-by-step explanation: