The Penn State women's soccer team had 17 players on their 2015-2016 roster. The team is composed of seven seniors, five juniors, three sophomores and two freshmen. The coach needs to choose four seniors, three juniors, one sophomore and one freshman for their starting line-up. How many different starting line-ups can be formed based on the coach needs?

I think that the answer would be three.

Step-by-step explanation:

step-by-step explanation:

if x = 2 you have to find x to finish the problem

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.