Which value of b will make the
expression x^2+bx+120 factorable?

Step-by-step expla These are the possible sums of the factor pairs of 12 b is the sum of the factors used to multiply to get 12 for the C value. ( x + 1) xx (x + 12) = x^2 + 13 x + 12 ( x - 1) xx (x - 12) = x^2 + (-13) x + 12 (x + 2) xx (x + 6) = x^2 + 8x + 12 (x - 2) xx (x - 6) = x^2 + (-8)x + 1

 12 b

These are the possible sums of the factor pairs of 12 b is the sum of the factors used to multiply to get 12 for the C value. ( x + 1) xx (x + 12) = x^2 + 13 x + 12 ( x - 1) xx (x - 12) = x^2 + (-13) x + 12 (x + 2) xx (x + 6) = x^2 + 8x + 12 (x - 2) xx (x - 6) = x^2 + (-8)x + 1

answer: you need the equation in the question so i can answer it

step-by-step explanation: