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The last one , because I will now solve it for you and prove therefore.

x²–4x+5=0;

D=(–4)²–4•5=16–20= –4= (2i)².

So:

x1= (4–2i)/2= 2–i

x2= (4+2i)2= 2+i.

This is the whole answer

Three other u will solve by yourself and have roots which will not be suitable.

ad = ae + ed = y + 7

similar triangles therefor

ac/ab = ad/ae

6/4 = (y + 7) / y

cross multiply

6y = 4(y + 7)

6y = 4y + 28

2y = 28

y = 14

step-by-step explanation:

a. is correct