Quadrilateral ABCD is a parallelogram. If the measure of angle A is 62 degrees and the measure of angle ADB is 75 degrees, what is the measure of angle ADC, in degrees?

Angle ADC = 180°-60° = 120°

Step-by-step explanation:

We could actually do without the additional detail pertaining to 75°. However, we could find angle CDB by difference. The solution would be 120°-75° = 45°. But this is not anymore needed by the problem because it is not asked. I guess the 75° is just a distraction.

part a: 1.08

part b: 27.59

m∠5 + m∠3 = m∠1   is true.

m∠5 + m∠6 = 180 is true

m∠2 +m∠3 = m∠6   is true

m∠2 +m∠3 +m∠5 = 180   is true