Write a function in the form y=mx+b for the line that contains the points (-6.4, -2.6 )and (5.2,9)

The function in the form y = mx+b will be:

y = x + 3.8

Step-by-step explanation:

We know that the slope-intercept form of the line equation

where

Given the points

Determining the slope between (-6.4, -2.6 )and (5.2,9)

Refine

substituting (5.2, 9) and m = 1 in the slope-intercept form of the line equation

y = mx+b

9 = 1(5.2) + b

b + 5.2 = 9

b = 9 - 5.2

b = 3.8

Therefore, the value of x = 3.8

now substituting b = 3.8 and m = 1 in the slope-intercept form of the line equation

y = mx+b

y = 1(x) + 3.8

y = x + 3.8

Therefore, the function in the form y = mx+b will be:

y = x + 3.8

answer: 5

step-by-step explanation:

no oblique asymptote

step-by-step explanation:

to find the oblique asymptote of f(x)

here numerator has degree 1 and denomintor degree 2

degree of numerator < degree of denominator

hence there is no oblique asymptote

when the degree of the denominator > that of the numerator, we saw that the value in the denominator got so much bigger, so quickly,   giving us a horizontal asymptote of the x-axis. or we can write

f(x) = a polynomial of x + a proper fraction.

in this case only we have oblique asymptotes but not when numerator has less degree.