Solve this system of equations. y = 5x +20 and y = -2x -8

y = 0

x = -4

( x, y ) = ( -4 , 0 )

Step-by-step explanation:

y = 5x + 20

y = -2x - 8

Substitute

5x + 20 = -2x - 8

Add 8 on both sides

5x + 20 + 8 = -2x - 8 + 8

5x + 28 = -2x

Subtract 5x on both sides

5x - 5x + 28 = -2x - 5x

28 = -7x

Divide by -7 on both sides

28/-7 = -7x/-7

-4 = x

Now that you have x, you can substitute it in one of the equations that was given to find the value of y.

y = 5x + 20

y = 5(-4) + 20

y = -20 + 20

y = 0

Or

y = -2x - 8

y = -2(-4) - 8

y = 8 - 8

y = 0

They will both be 0 no matter what

Point form = ( -4, 0 )

Hope this helped

hello from mrbilldoesmath!

answer:

25x^2 + 90x + 84

discussion:

mn(x) = m(n(x)) = m( 5x + 9) =

(5x + 9)^2 + 3 =>

25x^2 + 90x + 9^2 + 3 =

25x^2 + 90x + 84                 (as 9^2 = 9*9 = 81)

which is the second choice

regards,  

mrb

p.s.   i'll be on vacation from friday, dec 22 to jan 2, 2019. have a great new year!

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step-by-step explanation: