A concession stand at a football game sells hot dogs and popcorn. It costs the concession stand $2 to make each hot dog and $0.50 to make each bag of popcorn. They can spend no more than $200 to
buy the supplies needed for the hot dogs and popcorn. Which inequality can be used to determine
the possible combinations of hot dogs, h, and bags of popcorn, p, they can make based on the money
they have to spend?
O 2h +0.5p > 200
2h +0.5p < 200
O2p + 0.5h < 200
2p + 0.5h > 200

b i think

step-by-step explanation:

not really sure

nswer: a   y-axis

step-by-step explanation:

the answer is d

step-by-step explanation:

simplifying

5(x + -6) = 2(x + 3)

reorder the terms:

5(-6 + x) = 2(x + 3)

(-6 * 5 + x * 5) = 2(x + 3)

(-30 + 5x) = 2(x + 3)

reorder the terms:

-30 + 5x = 2(3 + x)

-30 + 5x = (3 * 2 + x * 2)

-30 + 5x = (6 + 2x)

solving

-30 + 5x = 6 + 2x

solving for variable 'x'.

move all terms containing x to the left, all other terms to the right.

add '-2x' to each side of the equation.

-30 + 5x + -2x = 6 + 2x + -2x

combine like terms: 5x + -2x = 3x

-30 + 3x = 6 + 2x + -2x

combine like terms: 2x + -2x = 0

-30 + 3x = 6 + 0

-30 + 3x = 6

add '30' to each side of the equation.

-30 + 30 + 3x = 6 + 30

combine like terms: -30 + 30 = 0

0 + 3x = 6 + 30

3x = 6 + 30

combine like terms: 6 + 30 = 36

3x = 36

divide each side by '3'.

x = 12

simplifying

x = 12

this should .