The scouts sold small and large boxes of cookies as a fund raiser. One scout sold 7 small boxes and 12 large boxes for $54.00. Another scout sold 5 small boxes and 10 large boxes for $60.00. The scout leader wrote a system of equations to represent the their sales. 7 x + 12 y = 54. 5 x + 10 y = 60.

Which constants can each equation be multiplied by so that one variable is eliminated when the equations are added? Check all that apply.
The first equation can be multiplied by 5 and the second equation by –6 to eliminate the y.
The first equation can be multiplied by –5 and the second equation by 6 to eliminate the y.
The first equation can be multiplied by –5 and the second equation by 7 to eliminate the x.
The first equation can be multiplied by 5 and the second equation by –7 to eliminate the x.
The first equation can be multiplied by –5 and the second equation by 10 to eliminate the x.

repeat the question

step-by-step explanation:

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step-by-step explanation:

step-by-step explanation:

12: 00 p.m. to 7: 00 p.m. is a total of 7 hours.

4: 00 p.m. to 7: 00 p.m. is a total of 3 hours.

this means that from 4: 00 p.m to 7: 00 p.m. this represents 3/7 of what was lost from 12: 00 p.m. to 7: 00 p.m.

after knowing this, after doing 11,600 - 6,800 = 4,800

4,800 represents 3/7 of what was lost for 7 hours.

we then divide 4,800 by 3 which gets 1,600.

because we know that 1,600 represents 1/7 of how much water was lost, we just have to multiply by 7, which gets 11,200.   after adding 11,200 to how much water was left at 7: 00 p.m. which was 6,800. 11,200 + 6,800 = 18,000

this means that the pool originally had 18,000 gallons in the pool.

you can also check your work by doing 18,000 - 4(1600), which becomes           1800 - 6400 which gets you 11,600.

susie has 7 apples