Write an equation of the line that passes through (3,2) and is perpendicular to the line y= 1/3x-3

Step-by-step explanation:

Given equation:

By comparing this to intercept form  , where m= slope , c=y-intercept.

Let n= slope of required line.

[Product of slope of two per perpendicular line =-1 ]

Equation of line passes through (a,b) and have slope m:

Equation of required line :

Hence, equation of the required line: y= -3x+11

idk but i found this "the graph of y = f(x-2) is the graph of y = f(x) translated two units rightward.  

so, since the point (9,2) lies on the graph of y = f(x), the point (11,2) lies on the graph of y = f(x-2)."

step-by-step explanation:

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