The data list shows the scores of ten students in Mr. Smith's math class. 61, 67, 81, 83, 87, 88, 89, 90, 98, 100 What is the standard deviation, to the nearest tenth, of the data if the scores represent a sample of Mr. Smith's students

12.3

Step-by-step explanation:

Step 1

We find the mean

The data list shows the scores of ten students in Mr. Smith's math class. 61, 67, 81, 83, 87, 88, 89, 90, 98, 100

Mean = Sum of terms/Number of terms

Number of terms = 10

Mean = 61 + 67 + 81 + 83 + 87 + 88 + 89 + 90 + 98 + 100/10

Mean = 844/10

Mean = 84.4

Step 2

Standard deviation

The formula for sample standard deviation =

√(x - Mean)²/n - 1

= √[(61 - 84.4)² + (67 - 84.4)² + (81 - 84.4)² + (83 - 84.4)² + (87 - 84.4)² + (88 - 84.4)² + (89 - 84.4)² + (90 - 84.4)² + (98 - 84.4)² + (100 - 84.4)²]/10 - 1

=√ 547.56 + 302.76 + 11.56 + 1.96 + 6.76 + 12.96 + 21.16 + 31.36 + 184.96 + 243.36/10 - 1

= √1364.4/9

= √151.6

= 12.31259518

Approximately to the nearest tenth = 12.3

The standard deviation = 12.3

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.

17.08

correct me if i am wrong.