Two trains leave towns kilometers apart at the same time and travel toward each other. One train travels slower than the other. If they meet in hours, what is the rate of each train

Complete question :

Two trains leave towns 1180 kilometers apart at the same time and travel toward each other. One train travels 19km/hr slower than the other. If they meet in 4 hours, what is the rate of each train

138 km/hr ; 157 km/hr

Step-by-step explanation:

Distance apart, d = 1180

Let :

Speed of A = x

Speed of A, = x - 19

Meeting time = 4 hours

Distance covered by A + Distance covered by B = total distance

Distance = speed * time

4 * (x - 19) + (4 * x) = 1180

4x - 76 + 4x = 1180

8x = 1180 + 76

8x = 1256

x = 1256 / 8

x = 157 km/hr

Speed of other train : (x - 19) = 157 - 19 = 138 km/hr

u = -(6/7)w

step-by-step explanation:

place all values with 'u' on one side of the equation.

4u + 8w = - 3u + 2w

4u + 3u = 2w - 8w

further simplify the equation by solving the addition and subtraction.

7u = - 6w

make 'u' the independent variable by placing its co-efficient on the right-hand side.

u = - (6/7)w