IS ANYONE SEEING MY QUESTIONS?? Find the standard equation for the circle with center on the negative y -axis and passing through the origin with radius of 3.

A. x^2 + y^2 = 9
B. (x + 3)^2 + y^2 = 9
C. x^2 + (y + 3)^2 = 9

Answer:

The correct option is C : x² + (y +3)² = 9 .

Step-by-step explanation:

We know that the general equation for a circle is ( x - h )² + ( y -k )²= r², Where,

Let the point be ( 0 , -y) , since it is on negative y axis . And the circle passes through the origin that is (0,0) . Hence the center will be 3 units down the y - axis that is ( 0 , -3) .Hence h will be 0 and y = (-3) .

Now its given that the radius of the circle is 3. So on substituting r = 3 , in standard form we have ,

⇒ ( x -h )² + ( y - k )²= r²

⇒ ( x - 0)² + { y - (-3) }² = 3²

⇒ x² + ( y + 3) ² = 3²

⇒ x² + ( y + 3)² = 9

• Note that I have attached the graph of the same .

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

step-by-step explanation:

given   that triangle lno is congruent to triangle lnm.

we have to fill up the blanks in the given question.

according to above order of congruency   kept in mind we can say that

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

ln ≅ ln due to common in both.

hence, by sas congruency,

the side angle side rule   states that if two sides and the included angle of one triangle are congruent to another triangle, then these two triangles are congruent.

answer

106 emergencies

step-by-step explanation: