PLEASE HURRY Move options to the blanks to show that ABC DEF using transformations, given the corresponding angles and sides are
congruent.
The first transformation is a
ofΔ ABC
The second transformation is a
ofΔ ABC
The transformations map AB onto
BC onto
CA onto
.ZA onto
ZB onto
and 2C onto
This demonstrates that A ABC =A DEF.
rotation
translation
reflection
up 2 units
down 2 units
90° clockwise about the origin
across the x-axis
across the y-axis
90° counter-clockwise about the origin
FD
EF
DE
ZF
ZE
ZD

- "runner b is moving at a slower rate."

- "the graphs shown are graphs of distance(km) against time(min).

the slopes of this graphs are are given by:

slope = (change in y)/(change in x)

= (change in distance)/(change in time)

this is the formula for finding the speed. so, the slope of these graphs represent the speed of the runner.

taking each division in the graph to represent 1 on both axis:

runner a ⇒ speed = (2-0)/(1-0)

= 2/1

= 2 km/min

runner b ⇒ speed = (3-0)/(3-0)

= 3/3

= 1 km/min

this shows that   runner b is moving at a slower rate."

33/100 is what i got