One x-intercept for a parabola is at the point (-2,0).
find the other x-intercept for the parabola defined in this equation:
y=2x^2+3x-2
separate the values with a comma

You can find the x intercept by setting y to 0 and factor the equation.

0=2x^3+3x-2
0=(2x-1)(x+2)

We can make this equation =0 if x is -2 and 1/2.

So the x intercepts are (-2,0) and (0.5,0)