Solve algebraically: x2 − x ≥ 6. A. x ≥ 3 and x ≥ −2
B. x ≥ 3 or x ≤ −2
C. x ≤ 3 and x ≤ −2
D. x ≤ 3 or x ≥ −2

A)  x ≥ 3 and x ≥ -2

The solution of the given equation

 x ≥ 3 and x ≥ -2

Step-by-step explanation:

Explanation:-

Given that x2 − x ≥ 6.

             ⇒ x² − x - 6.≥ 0

             ⇒ x² - 3 x + 2x -6 ≥ 0

             ⇒ x ( x-3) +2 ( x-3) ≥ 0

             ⇒ ( x -3) ( x+2) ≥ 0

               x -3 ≥ 0 and (x +2) ≥0

                x ≥ 3 and x ≥ -2

Final answer:-

The solution of the given equation

 x ≥ 3 and x ≥ -2

3.how is solving radical equations different than solving linear equations?

step-by-step explanation:

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