The one-to-one functions g and h are defined as follows.
HELP PLEASE

2, (x+13)/6, -7

Step-by-step explanation:

The -1 bit means do it backwards, so look the for the output of the function with the value given.

In g, when we put in 2 we get 9 out, so g^-1(9) is 2.

For the second one we need to rearrange it to get x = something.

h(x) + 13 = 6x

x = (h(x) + 13)/6

Then replace the h(x) with x and the x with h^-1(x) to get

h^-1(x) = (x + 13)/6

The last one is a trick. Note that h and h^-1 are opposites. If we do something then do the opposite of it, we haven't done anything at all! So the number stays the same.

step-by-step explanation:

given that ab is divided into equal parts as

ac, cd, de, ef, fg, gh, hi, ib.

from this we find that f is the midpoint of ab.

so using mid point formula we find

f = (3,7)

similarly considering fb, we get

h = mid point of fb = ((6,6) and g, mid point of fh is

g = (9/2, 13/2)

i is mid point of hb

so i =(15/2,11/2)