Please help . branliest anything ..A bag contains five yellow tickets numbered 1 though 5. The bag also contains four green tickets numbered 1 through 4. What is the probability that you pick a yellow ticket with an even number? option =5/7, 5/6, 1/6 and 1/2.

i got 3/5

Step-by-step explanation:

but i dont see that in your options

robert puts 2 in each row

hello from mrbilldoesmath!

answer:

a(n) - a(n-1) -3

discussion:

this ones a bit interesting. given a(n) = 5 - 3n consider this:

a(n-1) = 5 - 3(n-1)

          = (5 - 3n) + 3             => but a(n) = 5 - 3n, the first term

          = a(n)   + 3                 => subtract 3 from both sides

a(n-1) -3 = a(n)  

or

a(n) - a(n-1) -3

you,

mrb