A population of insects increases at a rate 230 + 8t + 0.9t2 insects per day (t in days). Find the insect population after 6 days, assuming that there are 50 insects at t = 0. (Round your answer to the nearest insect.)

The insect population after 6 days is of 1639 insects.

Step-by-step explanation:

A population of insects increases at a rate 230 + 8t + 0.9t2 insects per day

This means that

The population of insects after x days is given by:

So

In which K is the initital population(which is 50). So

After 6 days:

Rounding to the nearest insect, 1639

The insect population after 6 days is of 1639 insects.

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

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