An urn contains forty red chips and sixty white chips. Six chips are drawn out and discarded, and a sev- enth chip is drawn. What is the probability that the sev- enth chip is red

The probability that the 7th chip is red = 0.4

Step-by-step explanation:

Given that;

an urn contains 40 red chips and 60 white chips

6 chips are randomly drawn and discarded and a 7th chip is drawn,

lets consider E as the the event that represent the 7th chip is red.

so probability that 7th chip is red will be;

P(E) = ⁶∑ ×  /  

= × + ×  + ......+  /

= [ 2002554400 + ..... + 130504920 ] /

= 44821170240 / (1192052400)(94)

= 44821170240 / 112052925600

= 0.4

Therefore the probability that  the 7th chip is red = 0.4

don't know what that says sorry i can't you

step-by-step explanation:

idk what it says

step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2