Determain the equation, in slope intercept form, of the line of the line that has a slope of -6 and passes through the point P(-3, 2)

Step-by-step explanation:

The point-slope form of the equation is y - y₀ = m(x - x₀), where (x₀, y₀) is any point the line passes through and m is the slope:

m = -6

(-3, 2)    ⇒   x₀ = -3,  y₀ = 2

The point-slope form of the equation:

y - 2 = -6(x + 3)

So:

y - 2 = -6x - 18         {add 2 to both sides}

y = -6x - 16             ←  the slope-intercept form of the equation

ad = ae + ed = y + 7

similar triangles therefor

ac/ab = ad/ae

6/4 = (y + 7) / y

cross multiply

6y = 4(y + 7)

6y = 4y + 28

2y = 28

y = 14

step-by-step explanation: