Find the equation of the line that passes through (-1,2) and is perpendicular to y=1 – 2x. Leave your answer in the form y = mx + c

The equation of required line is .

Given:

A line passes through and is perpendicular to .

To find:

The equation of the line.

Explanation:

We have,

On comparing this equation with , we get

So, the slope of the given equation is .

The product of slopes of two perpendicular lines is always .

The slope of the required line is and it passes through the point . So, the equation of the line is:

Therefore, the equation of required line is .

Learn more:

link

The equation of the line that passes through (-1,2) and is perpendicular to y=1-2x is

Step-by-step explanation:

We need to write the equation of the line that passes through (-1,2) and is perpendicular to

The equation must be in form   has m equals to slope and c equals to y-intercept

So, we need to find slope and y-intercept.

Finding Slope

When the lines are perpendicular there slopes are opposite to each other.

Slope of given equation is:

We can write it as:

Comparing it with   we get m = -2

Now, The slope of given equation is: m = -2

The slope of required equation will be: m=

Finding y-intercept

Using point (-1,2) and slope m=, we can find y-intercept

So, y-intercept is: c =

Equation of line

Now, the equation of line having slope m=  and c = is:

So, the equation of the line that passes through (-1,2) and is perpendicular to y=1-2x is