Suppose that the functions s and t are defined for all real numbers x as follows. s(x)=2x-2
t(x)=3x
Write the expressions for (s-t)(x) and (s+t)(x) and evaluate (s⋅t)(-1)

Can't seem to figure it out

Step-by-step explanation:

Given functions are,

s(x) = 2x - 2

t(x) = 3x

(s - t)(x) = (2x - 2) - 3x

            = -x - 2

            = -(x + 2)

(s + t)(x) = (2x - 2) + 3x

             = 5x - 2

(s . t)(x) = (2x - 2)(3x)

            = 6x² - 6x

(s . t)(-1) = 6(-1)² - 6(-1)

            = 6 + 6

            = 12

sorry, i can't understand your question. will later if you describe more clearly!

: )

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step-by-step explanation: