Assume the figure below is a rhombus:
If DE=16x-3, EF=9x+11, and DF=52, find HG

9514 1404 393

  HG = √165 ≈ 12.8

Step-by-step explanation:

All sides of the rhombus are the same length, so ...

  DE = EF

  16x -3 = 9x +11

  7x = 14

  x = 2

  DE = 16(2) -3 = 29

Because the diagonals bisect each other, we have ...

  HF = DF/2 = 52/2 = 26

We know side GF is 29, so ...

  HG² + HF² = GF²

  HG² = GF² -HF² = 29² -26² = 165

  HG = √165 ≈ 12.8 . . . . rounded to tenths

where are the images of the functions i can only see the question you typed.

step-by-step explanation:

so firstly, we need to isolate the y variables to be able to solve these inequalities. firstly, add 0.5x on both sides of the first inequality and subtract 1.5x on both sides of the second inequality:

now since the slope is positive for the first inequality, this means that the line going upwards belongs to the first inequality, and the line going downwards belongs to the second inequality.

next, since y ≥ in the first inequality, this means that the shaded region will be above the first inequality's line, thus shading regions a and b.

next, since y ≤ in the second inequality, this means that the shaded region is going to be below this line, thus shading regions a and c.

since both lines shade region a, this means that region a is the solution.

step-by-step explanation:

mark brainliest!