The beginning balance of Cooper's savings account for the month of September was $5700, and it remained this way for the first 11 days of the month. On September 12, Cooper made a withdrawal of $900, so his balance changed, and it remained the same for a total of 9 days. On September 20, Cooper made a deposit of $1100, so his balance changed again, and it remained the same for a total of 10 days to finish out the month. Cooper's savings account has an APR of

Complete question :

The beginning balance of Cooper's savings account for the month of September was $5700, and it remained this way for the first 11 days of the month. On September 12, Cooper made a withdrawal of $900, so his balance changed, and it remained the same for a total of 9 days. On September 20, Cooper made a deposit of $1100, so his balance changed again, and it remained the same for a total of 10 days to finish out the month. Cooper's savings account has an APR of 3.65%, calculates interest daily, and pays interest at the end of the month. Cooper wants to calculate the amount he earned in interest during the month of September.

Part I: What interest rate does Cooper's savings account pay per day?

Part II: How much did Cooper earn in interest during the first 11 days of September?

0.01% ; $6.27

Step-by-step explanation:

Given :

Annual percentage interest (APR) = 3.65%

To obtain the daily interest :

APR / Number of days in a year

3.65% / 365

0.0365 / 365

= 0.0001

= 0.0001 * 100

= 0.01%

B.) Interest earned during first 11 days :

Using the relation :

Interest earned = Principal * Rate * Time

Principal = $5700 ; daily rate = 0.0001 ; number of days = 11

Interest earned = (5700 * 0.0001 * 11)

Interest earned = $6.27

it would be 6xy and -16xy.

problem:

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

f(5/2) = 10/3

i hope this !