Help please! area of rectangles and squares.

Step-by-step explanation:

area of rectangle

height×base

(2x-5)(2x-2)=

=4x^2-4x-10x+10

=4x^2-14x+10

(we get quadratic equation)

a=4 b=-14 c=10

firat find discriminant with formula:

D=b^2-4ac(-14)^2-(4×4×10)=196-160=36

now find x1 and x2 with formula:

X=(-b±√D)/2a

x1=(14+√36)/8=20/8=2.5

x2=(14-√36)/8=8/8=1

lets put values :

if we put x2 value as a base, which is 1 in given height and base, we will get 2(1)-2=0. measure of amy side can't be 0.

and if we put x2 in height, it will give us zero.

so no matter which one we put as value. we will get 0cm^2. so i think it cant be detected. im sorry if im wrong

this was already solved by me with a different person. if you look it up in the search bar at the top of the page, you will get the answer.

step-by-step explanation:

3< x< 5

step-by-step explanation:

|x - 4| < 1

there are two solutions, one positive and one negative.   remember to flip the inequality when taking the negative solution

x-4 < 1       x-4 > -1

add 4 to each side

x-4+4 < 1+4       x-4+4 > -1+4

x< 5                 x> 3

3< x< 5