F(x) = 3r2 + 12x + 5 What is the value of the discriminant of f?
D
How many distinct real number zeros does
f(x) have?

The value of the discriminant is 84.

i.e. b²- 4ac =  84

As

b²- 4ac > 0

Therefore, there are two distinct real number zeros.

Step-by-step explanation:

We know that the discriminant of the quadratic equation ax²+bx+c=0 is equal to b²- 4ac.

We also know that:

We are given

f(x) = 3x² + 12x + 5

comparing with the quadratic function ax²+bx+c=0

a = 3, b = 12, c = 5

Discriminant = b²- 4ac

                     = (12)²-4(3)(5)    ∵ a = 3, b = 12, c = 5

                     = 144 - 60

                     = 84

Thus, the value of the discriminant is:  84

As

b²- 4ac > 0

Therefore, there are two distinct real number zeros.

your answer would be 10x - 1

set each factor equal to 0

4x-3 = 0

2x-1 = 0

solve for x.

4x-3=0

4x=3

x= 3/4

solve for x. 

2x-1= 0

2x= 1

x= 1/2

your answer should be 1/2 is less than or equal to x and 3/4 is greater than or equal to x