If each interior angle of a regular polygon measures 120 , how many sides does the polygon have?

Interior angle of the polygon = [180(n - 2)]/n

where,

Let, The number of sides of polygon be n

➯ [180(n - 2)]/n = 120°

➯ 180n - 360 = 120n

➯ 180n - 120n = 360

➯ 60n = 360

➯ n = 360/60

➠ n = 6

answer: c

(2, -4)

goes 7 to the

(9, 4)

easy

the answer is 9 because the question is telling how much it be together.