See question in image.
Please show workings .

see explanation

Step-by-step explanation:

Given f(x) then the derivative f'(x) is

f'(x) = lim ( h tends to zero )

      = lim ( h to 0 )

     = lim ( h to zero )

     = lim ( h to zero )

     = ( lim h to 0 )

     = ( lim h to 0 )

     = lim ( h to 0 ) - ← cancel h on numerator/ denominator of both

     = lim( h to 0 ) 2(2x + h) - 1 ← let h go to zero

f'(x) = 4x - 1

for this pair of functions g(x)=x-2 and f(x)=|x| is (g o f)(a)= |a| -2

step-by-step explanation:

g(x)=x-2

f(x)=|x|

(g o f)(a)=?

(g o f)(x)=g(f(x))

(g o f)(x)=g(|x|)

(g o f)(x)=|x|-2

(g o f)(a)=|a|-2

a) 0,0; 1,1; and 2,2

step-by-step explanation:

these have the exact same coordinates, thus they are the correct function.