Write an equation in slope-intercept form perpendicular to the given equation through the given point Y = -3x + 4
(6,-2)

The equation in slope-intercept form perpendicular to the given equation through the given point (6,-2) is

Step-by-step explanation:

We need to write an equation in slope-intercept form perpendicular to the given equation through the given point

y = -3x + 4

(6,-2)

The general equation in slope intercept form is: where m is slope and b is y-intercept.

We need to find slope and y-intercept.

Finding slope:

The given line is perpendicular to required line, so there slopes are opposite

The slope of given line is m = -3, (By comparing it with general equation y=mx+b, we get m = -3)

The slope of required line is:

Finding y-intercept:

y-intercept can be found by using slope and the point(6,-2)

So, we get y-intercept b =0

Equation of required line:

So, the equation of required line having slope and y-intercept b =0 is:

So, the equation in slope-intercept form perpendicular to the given equation through the given point (6,-2) is

the answer is b.)

< 1=< 2

ab will be equal to