Suppose the amount of a popular sport Drink in bottles leaving the Filling machine has a normal distribution with me 101.5 ml and standard deviation 1.6 if 36 bottles are randomly selected, find the probability that the mean is less than 102.1ml

0.98778

Step-by-step explanation:

Given :

Mean, m = 101.5

Standard deviation, s = 1.6

Sample size, n = 36

Sample mean, x = 102.1

P(x < 102.1)

Zscore = (x - m) / s/sqrt(n)

Zscore = (102.1 - 101.5) / (1.6/√36)

Zscore = 0.6 / 0.2666666

Z = 2.25

P(Z < 2.25) = 0.98778 (Z probability calculator)

irrational, cannot

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