Pls help me, i’ll give

Answer/Step-by-step explanation:

First, find the slope (m) of Line L using the points (0, 5) and (2, 1):

Slope (m) = -2

✔️Since the line is parallel bro Line L, it would also have the same slope value of -2.

We can use the slope (m) and a point (a, b) of the line to find its equation using the point-slope formula, y - b = m(x - a).

Substitute (a, b) = (3, 0), and m = -2 into y - b = m(x + a):

Thus,

✅y - 0 = -2(x + 3)

Rewrite equation in slope-intercept form

y = -2(x + 3)

✅y = -2x - 6

δabc ≅ δdcb by sas because

db ≅ ac . . given (side)

bc ≅ bc . . reflexive property (side)

∠dbc ≅ ∠ acb . . alternate interior angles where transversal bc crosses parallel lines bd and ac (included angle)