Six times the sum of three consecutive odd integers is 18.Find the integers 1st integers (smallest of 3): 2nd integers (middle of 3): 3rd integers (largest of 3):

-1, 1 and 3.

Step-by-step explanation:

Let the integers be n, n + 2 and n + 4, then

6( n + n+2 + n + 4) = 18

6(3n + 6) = 18    Divide through by 6:

3n + 6 = 3

3n = -3

n = -1

So the integers are -1, 1 and 3.

1,918

step-by-step explanation:

the answer is c)8

step-by-step explanaction: