You spin the spinner, flip a coin, then spin the spinner again. Find the probability of the compound event. Spinning blue, flipping heads, then spinning a 1 Spinning an odd number, flipping heads, then spinning yellow Spinning an even number, flipping tails, then spinning an odd number Not spinning red, flipping tails, then not spinning an even number

Hence, the probability of the NOT spinning a RED, flipping TAILS, and then NOT spinning and EVEN number is:

2/9

The spinner contains three colors Red, Blue and Yellow.

Let P denote the probability of an event.

Let A denote the event that red color is not obtained on the spinner.

B denote the event that tail is obtained on flipping a coin.

and C denote the event that an odd number is not obtained on spinner.

Hence,

P(A)=2/3

( Since out of three choice 2 are not red)

P(B)=1/2

( Since the only outcomes are H and T which have equal chances to come up)

and

P(C)=2/3

( Since the number on the spinner are 1,2 and 3 out of which only one is even)

Clearly all the events are independent.

Hence, the probability of the compound event is:

= 2/3 x 1/2 x 2/3

= 2/9

Other explanation

The correct answer is 2/9

2/3 = not spinning red

1/2 = flipping tails

2/3 = not spinning an even number

Then you have to multiply all the fractions together

2/3×1/2×2/3= 2/9

the expected value of the random variable : 0, 1 and 2

step-by-step explanation:

step-by-step explanation: