Solve the equation 2(h-8) - h=h - 16

A h = 8

B h= -8

C h = infinitely many solutions

D h = no solution

2(h-8)-h=h-16

2(h-8)=h+h-16

2(h-8)=2h-16

2(h-8)=2(h-8)

h-8=h-8

h-h=8-8

0=0 so their can be infinite value of h.

hence c is correct

we can put in place of anything but answer will be zero.

1/5

step-by-step explanation:

the dice has 6 sides and there is only one 5 in a dice.

a complex number is a number that can be expressed in the form a + bi, where a and b are real numbers, and i is a solution of the equation x2 = −1. because no real number satisfies this equation, i is called an imaginary number. has no real solution, since the square of a real number cannot be negative.