If an object is propelled upward from a height of 48 feet at an initial velocity of 96 feet per second, then its height after t seconds is given by the equation h(t)= -16t2+96t +48, where height is in feet. After how many seconds will the object reach a height of 192 feet?

the number of seconds to reach the height is 3 seconds

Step-by-step explanation:

The computation of the seconds that reach the height is as follows;

Given that

h = -16t^2 + 96t + 48

here

H = 192 feet

So,

192 = -16t^2 + 96t + 48

-16t^2 + 96t - 144 = 0

Divide by -16

t^2 - 6t + 9 = 0

t^2 - 3t - 3t + 9

t(t - 3) - 3(t - 3)

t = 3 seconds

Hence, the number of seconds to reach the height is 3 seconds

can you give me more detail on this! ?

step-by-step explanation:

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