Mathematics, 16.01.2021 16:20 bear342

It takes 6 workers from the Fast Movers Company 10 hours to unload 6 trucks. It takes 10 workers from the Careful Movers Company 8 hours to load 2 trucks. How long would it take 4 workers from the Fast Movers Company and 8 workers from the Careful Movers Company to unload 8 trucks?

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The time it would take 4 workers from the Fast Movers Company and 8 workers from the Careful Movers company to unload 8 trucks is 13 hours and 20 minutes

Step-by-step explanation:

The time it takes 6 workers from the Fast Movers Company to unload 6 trucks = 10 hours

The time it takes 10 workers from the Careful Movers Company to load 2 trucks = 8 hours

Therefore, when 1 worker of the Fast Movers Company is unload 1 truck each of the 6 trucks it takes 10 hours

Which gives the time for 1 worker of the Fast Movers Company is unload 1 truck = 10 hours, which gives;

10 worker hours per truck or 10 worker·h/(truck)

Similarly we have;

The time it takes 10 workers of the Careful Movers Company to load 2/2 = 1 truck = 8/2 = 4 hours

Therefore, the time it would take 1 worker of the Careful Movers Company to load 1 truck = 10 × 4 hours = 40 hours, which gives;

40 worker·h/(truck)

Let "t" represent the time it would take 4 workers from the Fast Movers Company and 8 workers from the Careful Movers Company to unload 8 trucks

We have;

$\dfrac{4 \ workers \times t }{\left (\dfrac{10 \ worker \cdot hour}{truck} \right ) } + \dfrac{8 \ workers \times t }{\left (\dfrac{40 \ worker \cdot hour}{truck} \right ) } = 8 \ trucks$

Which can be simplified as follows;

$\dfrac{4 \ trucks \times t }{10 \cdot hour} + \dfrac{8 \ trucks \times t }{40 \cdot hour} = t \times \left ( \dfrac{4 \ trucks }{10 \cdot hour} + \dfrac{8 \ trucks }{40 \cdot hour} \right ) = 8 \ trucks$

$t = \dfrac{8 \ trucks}{\left ( \dfrac{4 \ trucks }{10 \cdot hour} + \dfrac{8 \ trucks }{40 \cdot hour} \right ) } = \dfrac{8 \ trucks}{\left ( \dfrac{3 \ trucks }{5 \ hour} \right ) } = \dfrac{5 \ hour\times 8 \ trucks}{3 \ trucks } \right ) } = \dfrac{40}{3} \ hours$

t = 40/3 hours = 13 hours and 20 minutes

The time it would take 4 workers from the Fast Movers Company and 8 workers from the Careful Movers company to unload 8 trucks = 13 hours and 20 minutes

Answer from: Quest

step-by-step explanation:

Answer from: Quest

$\begin {array}{c|c}\underline {\quad x\quad}& \underline{\quad y\quad}\\ -2& 4\\-1& 2\\0& 0\\1& 2\\ 2& 4\\\end{array}$

step-by-step explanation:

y = | -2(-2) | → y = | 4 | → y = 4 ⇒ (-2, 4)

y = | -2(-1) | → y = | 2 | → y = 2 ⇒ (-1, 2)

y = | -2(0) | → y = | 0 | → y = 0 ⇒ (0, 0)

y = | -2(1) | c → y = | -2 | → y = 2 ⇒ (1, 2)

y = | -2(2) | → y = | - 4 | → y = 4 ⇒ (2, 4)

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