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1a) 67.2 kg

1b) 66.5 kg

1c) 64 kg, 68 kg

2a) Mean = 58.1m, Median = 55m, Mode = 49m

2b) The mode is not a good measure since all data except 49m appeared twice i.e. the data set is quite distributed. (sorry I am not very sure with this answer)

3a) Independent variable is time, Dependent variable is distance.

3b) See attachment.

3c) Linear

3d) 2.5s: 10m 6.25s: 25m 8s: 32m

3e) 3m: 0.75s 21m: 5.25s. 36m: 9s.

Step-by-step explanation:

1a) Mean = (74+71+68+84+54+60+64+68+65+64)/10 kg = 67.2 kg

1b) Sort the data in ascending order (in kg).

54 60 64 64 65 68 68 71 74 84

Median = (65+68)/2 kg = 66.5 kg

1c) Mode = 64 kg, 68 kg (both appeared twice)

2a) Mean = (45+52+47+55+62+80+71+60+84+57+46+50+48+61+49+63+54+49+72)/19 m =  58.1m (correct to 1 decimal place)

Arrange the data in ascending order (in m).

45 46 47 48 49 49 50 52 54 55 57 60 61 62 63 71 72 80 84

Median = 55m

Mode = 49m (appeared twice)

2b) See answer.

3a) Independent variable is the variable that is to be changed. Dependent variable is the variable that is to be measured.

3b) Just plot the graph.

3c) Distance = 4 x time

3d) 2.5 x 4 = 10m. 6.25 x 4 = 25m. 8 x 4 = 32m.

3e) 3/4=0.75s. 21/4=5.25s. 36/4=9s.

you never say the total so we cant find the percentage used for petrol

step-by-step explanation:

f(2x−x2)=−3x2+6x−1

step-by-step explanation:

set up the composite function and evaluate.

f(2x−x2)=−3x2+6x−1