PLEASE HELP ME!! :( If f(x) = 4x ^ 2 - 6 and g(x) = x ^ 2 - 4x - 8 , find (f - g)(x)
A. (f - g)(x) = 3x ^ 2 - 4x - 2
B. (f - g)(x) = 3x ^ 2 + 4x + 2
C. (f - g)(x) = 5x ^ 2 - 4x - 14
D. (f - g)(x) = - x ^ 2 - 14

Step-by-step explanation:

(f - g)(x)

= f(x) - g(x)

= (4x² - 6) - (x² - 4x - 8)

= 4x² - 6 - x² + 4x + 8

= 3x² + 4x + 2. (B)

g = (2, 2)

step-by-step explanation:

given the ratio is 1 : 1 then f is the midpoint of eg

let the coordinates of g = (x, y)

using the midpoint formula

(0 + x) = 1 ( multiply both sides by 2 )

0 + x = 2 ⇒ x = 2

similarly

(4 + y) = 3 ( multiply both sides by 2 )

4 + y = 6 ( subtract 4 from both sides )

y = 2

coordinates of g = (2, 2)

relating to or denoting a system of numbers and arithmetic based on the number ten, tenth parts, and powers of ten.

it alot will look like this 4.4