Points A and C are vertices of a cube with a side length of 2 cm, and B is the point of the intersection of the diagonals of one face of the cube, as shown below.
Determine the length of CB.

9514 1404 393

  CB = √6 cm

Step-by-step explanation:

The diagonal of a square is √2 times the edge length, so the length AB will be (1/2)√2(2 cm) = √2 cm.

Then the length CB is given by the Pythagorean theorem as ...

  CB = √(AC^2 +AB^2) = √((2 cm)^2 + (√2 cm)^2) = √(4 +2) cm

  CB = √6 cm

answer: 94

step-by-step explanation: 79+91+92+94+94 = 450 divided by 5 (since there are 5 number that are being added) = 90

multiple all that

step-by-step explanation:

27×17