The Pythagorean triple (5, 12, 13) can't be generated from the identity (x2 - 1)2 + (2x)2 = (x2 + 1)2. which has only one variable, because the length of the hypotenuse (13 units) and the length of the longer
of the other two legs (12 units) are not 2 units apart.
Find a two-variable identity by incorporating a second variable, yl into the single-variable identity. Note
that x > 1, x > y, and x and y are positive integers.
Select the correct answer.
o (x2 - y2)2 – (2xy)2
(x2 + y2)
o (x2 + y2)2 + (2xy)2 = (x2 - y2)2
© (x2 - y2)2 + (2xy)2 = (x² + y2)?
o (x2 - y2)2 + (2xy)2 = (x2 - y2)2

no solution

step-by-step explanation:

there is not enough information in the problem to solve.

a.   we have two

lines:   y = 4-x   and  

y = 8-x^-1

given two simultaneous equations that are both to be

true, then the solution is the points where the lines cross. the intersection is

where the two equations are equal. therefore the solution that works for both

equations is when

4-x = 8-x^-1

this is where the two lines will cross and that is the

common point that satisfies both equations.

b.   4-x = 8-x^-1

  x           4-x       8-x^-1

-3           7        

8.33

-2           6         8.5

-1           5         9

  0           4        

-

  1           3        

7

  2           2        

7.5

  3           1         7.67

the table shows that none of the x values from -3 to 3 is

the solution because in no case does

4-x = 8-x^-1

to find the solution we need to rearrange the equation to

find for x:

4-x = 8-x^-1

multiply both sides with x:

4x-x^2 = 8x-1

x^2+4x-1=0

x= -4.236, 0.236

therefore there are two points that satisfies the

equation.

find y:  

x=-4.236

y = 4-x   = 4 – (-4.236)

= 8.236

y = 8-x^-1 =   .236)^-1

= 8.236

x=0.236

  y = 4-x   = 4 – (0.236) = 3.764

y = 8-x^-1 =   8-(0.236)^-1

= 3.764

thus the two lines cross at 2 points:

(-4.236, 8.236) & (0.236, 3.764)

c.   to solve

graphically the equation 4-x = 8-x^-1

we would graph both lines: y = 4-x   and   y

= 8-x^-1

the point on the graph where the lines cross is the

solution to the system of equations.

just graph the points on part b on a cartesian coordinate

system and extend the two lines.   the

solution is, as stated, the point where the two lines cross on the graph.

step-by-step explanation:

mark brainliest!

what’s the question?