So if x +3y =1 how do i plug it in to -x +2y =4 -x +3y=1-x
3y/3=1-x/3
y=1/3 - x/3
y=-1/3x +1/3
Then I have to plug x into the y= the fractions confuse me

If x + 3y = 1, then x = 1 - 3y.

Then in the second equation, replace x with 1 - 3y :

-x + 2y = 4

- (1 - 3y) + 2y = 4

-1 + 3y + 2y = 4

-1 + 5y = 4

5y = 5

y = 1   →   x = -2

since x = 1 - 3•1 = 1 - 3 = -2.

Alternatively, you can instead solve for y in the first equation, so that if x + 3y = 1, you get

x + 3y = 1

3y = 1 - x

y = (1 - x)/3

Then replace y in the second equation:

-x + 2y = 4

-x + 2 ((1 - x)/3) = 4

-x + 2/3 (1 - x) = 4

Multiply both sides by 3 to get rid of the fraction:

-3x + 2 (1 - x) = 12

-3x + 2 - 2x = 12

-5x + 2 = 12

-5x = 10

x = -2   →   y = 1

since y = (1 - (-2))/3 = (1 + 2)/3 = 3/3 = 1.

it's equivalent, so we can say that its equal.

let's call the denominator x and the numerador is 18 less then denominator, x - 18.

multiply

2.x = 5.(x - 18)

2x = 5x - 90

90 = 5x - 2x

90 = 3x

x = 90/3

x = 30

so: