PLZ I REALLY NEED HELP Find the values of x and y in parallelogram PQRS 15. PT=x+2, TR=y, QT=2x, TS=y+3
PLZ ANSWER ASAP DUE IN 30 MINS I WILL BE AWARDING 20 POINTS AND BRAINLIEST ANSWER TO whoever CAN SOLVE THIS

x = 5 and y = 7

Step-by-step explanation:

Given that,

PT = x+2, TR=y, QT=2x, TS=y+3

We need to find the value of x and y.

The diagonal of a parallelogram bisect each other. It means,

PT = TR and QT = TS

ATQ,

y = x+2 ...(1)

and

y+3 = 2x ....(2)

Subtracting equation (1) and (2).

y-(y+3) = x+2-2x

y-y-3 = 2-x

-3 = 2-x

x = 2+3

x = 5

Put the value of x in equation (1).

y = 5 + 2

y = 7

Hence, the values of x and y are x = 5 and y = 7.

a

explanation: