Awater tank has the shape of an inverted right circular cone with base radius 3 meters and height 6 meters. water is being pumped into the tank at the rate of 12 meters3/sec. find the rate, in meters/sec, at which the water level is rising when the water is 2 meters deep. give 2 decimal places for your answer. type your answer in the space below. if your answer is a number less than 1, place a leading "0" before the decimal point (ex: 0.35).

the rate of change is 3.8m/s

Step-by-step explanation:

The volume of the right circular cone is

The rate of change of volume is

In order to proceed further we have to define r in terms of h so tht we can compute the derivative above.

The ratio between h and r is

Therefore .

We plug that into the derivative above and get:

Thus

Now for the numerical part.

The rate of change of volume is , so when the water is 2 meters deep , therefore:

step-by-step explanation:

one of the most important purposes of surface treatment is to alter surface properties according to the requirement of specific applications. for example, hydrophobic coating has been utilized on windshield and eyeglasses. gold atom monolayer on substrate has become a popular surface bioconjugation strategy.