The speed limit on a road drops down to 15 miles per hour around a curve. Mr. Gerard slows down by 10 miles per hour as he drives around the curve. He never drives above the speed limit. At what speed (s) was Mr. Gerard driving before the curve? Write and solve an inequality

Answer Mr. Gerard speed was at most 25 miles per hour before the curve

Step-by-step explanation:

How to solve the speed Mr. Gerard was driving before the curve

Let’s just assume that Gerard went exactly the speed limit 15 miles per hour (mph) after when he slowed down by 10 miles per hour and drove around the curve. The reason why I’m using exactly 15mph is because it’s the max speed he can go. He can go 15 miles per hour and still be safe, but it’s just that he can’t go any faster than that.

Now, you can do 15 + 10 to find the speed he went before he drove around the curve. So, that would be 25mph before he drove around the curve.

You might be asking: What if he went slower than 25mph before he drove around the curve, and what if he went faster than 25mph?

-When he drives exactly 25mph and slows down by 10mph when he makes the turn around the curve, he’s going exactly 15mph which it safe for him because it’s not faster than 15mph.

-It could be possible that he went slower than 25mph before he drove around the curve, but he still will be safe because when he makes the turn around the curve and slows down by 10 miles per hour, now he’ll reach below 15 miles per hour which is even safer for him. Here’s an example for you to understand: Let’s say he drove 23mph before the curve (which is less than 25mph). As soon as he makes the turn around the curve, he slows down by 10mph. So after he goes around the curve, he’s going 13mph, which is less than the speed limit 15mph. You can take any number less than 25mph and he’ll still be safe because it will be less than 15mph.

-Now, if he went faster than 25mph, he wouldn’t be safe anymore because after when he slows down by 10mph and goes around the curve, he’ll be above the speed limit of 15mph. Here’s an example for you to understand: Let’s say he drove 27mph before the curve (which is faster than 25mph). As soon as he makes the turn around the curve, he slows down by 10mph. So after he goes around the curve, he’s going 17mph, which is faster than the speed limit 15mph.

Mr. Gerard speed was at most 25 miles per hour before the curve

Graphing it

A way to graph this is to write out a compound inequality. You can write it as:

0 < y ≤ 25  ⇒ Where any speed has to be less than or equal to 25 miles per hour, because 25 miles per hour is the most/biggest speed Mr. Gerard can drive. But it has to be greater than 0 because you can’t go negative miles per hour, or 0 miles per hour

The graph is shown below ↓

I don’t know what graph you want, or how your teacher wants you to graph it. So I put two options for you :)

I hope you understand and that this helps with your question! :)

the answer is su.k.my? ? co.kc

when functions are first introduced, you will probably have some simplistic "functions" and relations to deal with, usually being just sets of points. these won't be terribly useful or interesting functions and relations, but your text wants you to get the idea of what the domain and range of a function are. small sets of points are generally the simplest sorts of relations, so your book starts with those.

step-by-step explanation:

state the domain and range of the following relation. is the relation a function?

{(2, –3), (4, 6), (3, –1), (6, 6), (2, 3)}

the above list of points, being a relationship between certain x's and certain y's, is a relation. the domain is all the x-values, and the range is all the y-values. to give the domain and the range, i just list the values without duplication:

domain: {2, 3, 4, 6}

range: {–3, –1, 3, 6}

(it is customary to list these values in numerical order, but it is not required. sets are called "unordered lists", so you can list the numbers in any order you feel like. just don't duplicate: technically, repetitions are okay in sets, but most instructors would count off for this.)

while the given set does indeed represent a relation (because x's and y's are being related to each other), the set they gave me contains two points with the same x-value: (2, –3) and (2, 3). since x = 2 gives me two possible destinations (that is, two possible y-values), then this relation is not a function.

note that all i had to do to check whether the relation was a function was to look for duplicate x-values. if you find any duplicate x-values, then the different y-values mean that you do not have a function. remember: for a relation to be a function, each x-value has to go to one, and only one, y-value.

state the domain and range of the following relation. is the relation a function?

{(–3, 5), (–2, 5), (–1, 5), (0, 5), (1, 5), (2, 5)}

i'll just list the x-values for the domain and the y-values for the range: